In △s ADE and ABC, ∠DAE=∠BAC (Common angle) ∠ADE=∠ABC (Corresponding angles of parallel lines) ∠AED=∠ACB (Corresponding angles of parallel lines) Therefore, △ADE∼△ABC (AAA rule) Hence, ADAB=DEBC ADAD+DB=DEBC 11+DBAD=DEBC 11+45=DEBC 59=DEBC
In the adjoining figure, DE || AB,
AD = 7 cm, CD = 5 cm and BC = 18 cm
Find (i) BE (ii) CE