In the adjoining figure- - ABC is right-angled at B and - A-45-If-AC-3-2 cm- find i BC- ii AB-

Sin A= Opposite side/Hypotenuse side sin 45 = BC/AC 1/√(2) = BC/3√(2) BC = 3 cm cos A= Adjacent side/Hypotenuse side cos 45 = AB/AC 1/√(2) = AB/3√(2) AB = 3 cm ...

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Standard X

Mathematics

Trigonometric Ratios

In the adjoin...

Question

In the adjoining figure, $Δ A B C$ is right-angled at B and $∠ A = 45^{\circ} . I f A C = 3 \sqrt{2}$ cm, find (i) BC, (ii) AB.

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Solution

$s i n A = \frac{O p p o s i t e s i d e}{H y p o t e n u s e s i d e}$

$s i n 45 = \frac{B C}{A C}$

$\frac{1}{\sqrt{2}} = \frac{B C}{3 \sqrt{2}}$

$B C = 3 c m$

$c o s A = \frac{A d j a c e n t s i d e}{H y p o t e n u s e s i d e}$

$c o s 45 = \frac{A B}{A C}$

$\frac{1}{\sqrt{2}} = \frac{A B}{3 \sqrt{2}}$

$A B = 3 c m$

AB = BC = 3 cm

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In the adjoining figure, ΔABC is right-angled at B and ∠A=45∘. If AC=3√2 cm, find (i) BC, (ii) AB.

sinA=Opposite sideHypotenuse side sin45=BCAC 1√2=BC3√2 BC=3 cm cosA=Adjacent sideHypotenuse side cos45=ABAC 1√2=AB3√2 AB=3 cm AB = BC = 3 cm

In the adjoining figure, $Δ A B C$ is right-angled at B and $∠ A = 45^{\circ} . I f A C = 3 \sqrt{2}$ cm, find (i) BC, (ii) AB.