Question

In the adjoining figure, find the measure of $\angle BCD$

Answer 1

$\angle ABC={115}^o$

$\angle CDE={110}^o$

$\angle CBF={65}^o$

$\therefore \angle CFG={110}^o$

$\therefore \angle CFB={70}^o$

$\angle CBF+\angle CFB+\angle BCF={180}^o$

$65+70+\angle BCF=180$

$\angle BCF=180-135$

$\angle BCF=45$