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Question

In the adjoining figure, find the perimeter of the shaded region where ADC, AEB and BFC are semi-circle on diameter AC, AB and BC respectively.
1127878_b4970d8a749a4797aff0de3397f55e9b.png

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Solution

Given:
Diameter of semicircle AEB=2.8 cm
radius of semicircle (AEB)=282=1.4 cm
Diameter of semicircle BFC=1.4 cm
radius of semicircle (BEC)=1.42
Diameter of semicircle ADC=2.8+1.4=4.2 cm
radius of semicircle (ADC)=4.212=2.1cm
perimeter of shaded region = and sum of arc of semicircle AEB,
BFCand ADC=[(π×1.4)+(π×0.7)+(π×2.1)]cm
=π(1.4+0.7+2.1)cm
=(227)×.4
=22×.6
=13.2cm
Perimeter of shaded region is 13.2 cm


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