In the adjoining figure given below ST∥QR, then what is the value of y?
A
5
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B
9
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C
12
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D
15
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Solution
The correct option is B 9 Since,ST∥QR⇒PSSQ=PTTR(by mid-point theorem) ⇒PSSQ+1=PTTR+1 ⇒PS+SQSQ=PT+TRTR or ⇒PQSQ=PRTR ⇒2yy−3=2y+3y−2 ⇒2y2−4y=2y2−6y+3y−9 ⇒−4y=−3y−9 ⇒y=9