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Question

In the adjoining figure, if 10 calorie heat is produced per second in 5Ω resistor due to the flow of current through it, then the heat produced in 6Ω resistor is
679173_0b75c0fe98c14d62acee5fe4a7672693.png

A
1 cal/s
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B
2 cal/s
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C
3 cal/s
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D
4 cal/s
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Solution

The correct option is C 3 cal/s
Given, heat produced per second in 5Ω resistor
=10 cal/s=10×4.2J/s
So, V25=10×4.2
or V=10×4.2×5V=42×5V
Potential difference across A and B=42×5
So, current in 6Ω,
I=42×510ampere
Hence, heat produced in it,
H=(42×510)2×6 J/s
=64.2×64.2=3 cal/s.

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