In the adjoining figure, if 10 calorie heat is produced per second in 5Ω resistor due to the flow of current through it, then the heat produced in 6Ω resistor is
A
1cal/s
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B
2cal/s
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C
3cal/s
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D
4cal/s
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Solution
The correct option is C3cal/s Given, heat produced per second in 5Ω resistor =10cal/s=10×4.2J/s So, V25=10×4.2 or V=√10×4.2×5V=√42×5V Potential difference across A and B=√42×5 So, current in 6Ω, I=√42×510ampere Hence, heat produced in it, H=(√42×510)2×6J/s =64.2×64.2=3cal/s.