Question

In the adjoining figure, if $\angle COA-\angle BOC={50}^o$, find these angles.

Answer 1

In the figure,

$\angle COA-\angle BOC={50}^o$ ....... $\left(i\right)$ [Given]

We know that, $\angle BOC+\angle COA={180}^o$

$⟹\angle BOC+{50}^o+\angle COA={180}^o$

$⟹2\angle BOC={180}^o-{50}^o={130}^o$

$⟹\angle BOC={65}^o$

From $\left(i\right)$,

$\angle COA-{65}^o={50}^o$

$⟹\angle COA={115}^o$

Hence, $\angle BOC={65}^o$ and $\angle COA={115}^o$