Given:
Line p || line q and line l are transversal.
Line l || line m and line p is a transversal.
Line p || line q and line m is a transversal.
Firstly let us find the measure of ∠a
Line p || line q and line l are transversal.
So,
∠a+80°=180° [Since, they are interior angles]
∠a=180°–80°
∠a=100°
Now, line l || line m and line p is a transversal.
So, ∠c=80° … (i) [By using exterior alternate angles]
Line p || line q and line m is a transversal.
So, ∠b=∠c … [Since, they are corresponding angles]
∠b=80° … [From equation (i)]
∴ The measure of ∠a is 100°,∠b is 80°,∠c is 80°.