In the adjoining figure line p $| |$ line q. Line t and line s are transversals. Find measure of $∠$ x and $∠$ y using the measures of angles given in the figure.

Open in App

Solution

$40^{\circ} + u = 180^{\circ} \Rightarrow u = 140^{\circ} ω + u = 180^{\circ} \Rightarrow ω = 180 ° - u = 40 ° ∠ z = 70 °$ (vertically opposite angles)
$∠ y + ∠ z = 180 °$
$\Rightarrow ∠ y = 180 ° - ∠ z 180 ° - 70 ° = 110 °$
$\Rightarrow ω + x = 180^{\circ}$
$∴ x = 140^{\circ}$

Suggest Corrections

Similar questions

Q. In the adjoining figure line

p | |

line

q

. Line

‘ t^{'}

and line

‘ s^{'}

are transversals. Find the measure of

∠ x

and

∠ y

using the measures of angles given in the figure.

Q. In the adjoining figure. line p ∥ line q. line l ∥ line m. Find measures of ∠a, ∠b and ∠c, using the measures of given angles. Justify your answers.

Q. In the adjoining figure, line a ∥ line b. Line l is a transversal. Find the measures of ∠x, ∠y, ∠z using the given information.

In the given figure, line p || line q and line l and line m are transversals. Measures of some angles are shown.

Hence find the measures of

∠ a, ∠ b, ∠ c, ∠ d .

In the given figure, line $p$ is parallel to the line $q$ . Line $l$ and line $m$ are transversals. Measures of some angles are shown. Find the measures of $∠ a$ and $∠ c$ .

Join BYJU'S Learning Program

In the adjoining figure line p|| line q. Line t and line s are transversals. Find measure of ∠x and ∠y using the measures of angles given in the figure.

40∘+u=180∘⇒u=140∘ω+u=180∘⇒ω=180°−u=40°∠z=70°(vertically opposite angles)∠y+∠z=180°⇒∠y=180°−∠z180°−70°=110°⇒ω+x=180∘∴x=140∘

In the adjoining figure line p $| |$ line q. Line t and line s are transversals. Find measure of $∠$ x and $∠$ y using the measures of angles given in the figure.