In the adjoining figure, O is the centre of the circle and B is a point of contact. Seg OE⊥ seg AD, AB=12,AC=8, find
i. AD
ii. DC
iii. DE.
Open in App
Solution
i. Line AB is the tangent at point B and seg AD is the secant. [Given] ∴AC×AD=AB2[ Tangent secant segments theorem] ∴8×AD=122∴8×AD=144∴AD=1448∴AD=18 units
ii. AD=AC+DC[A−C−D] ∴18=8+DC ∴DC=18−8 ∴DC=10 units
iii. seg OE⊥ seg AD[Given]
i.e. seg OE⊥ seg CD[A−C−D]
∴DE=12DC [Perpendicular drawn from the centre of the circle to the chord bisects the chord] =12×10 ∴DE=5 units