Question

In the adjoining figure O is the centre of the circle The radius OP bisects a rectangle ABCD at right angle If DM = NC = 2 cm and AR = SB = 1 cm and KS = 4 cm and OP = 5 cm then the area of the rectangle ABCD is ______

• A. $8c{m}^2$
• B. $10c{m}^2$
• C. $12c{m}^2$
• D. None of these

Answer 1

The correct option is B $10c{m}^2$

In the adjoining figure O is the centre of the circle The radius OP bisects a rectangle ABCD at right angle If DM = NC = 2 cm and AR = SB = 1 cm and KS = 4 cm and OP = 5 cm
THEN AB=AR+RK+KS+SB
Or AB=1+1+4+4=10 cm
Diff of DM or NC with AR& SB is 2-1=1
Then AD=LK=BC=1 cm
So the area of the rectangle ABCD =$AB\times BC=10\times 1=10c{m}^2$