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Question

In the adjoining figure P,M,Q,R are collinear and

PM = MQ = MS, SR2 = PR . QR. Then


A


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B


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C


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D


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Solution

The correct option is A



The given condition is SR2 = PR. QR.
M is the circum centre of
∆PQS and

As SR2 = PR. QR , RS is the tangent to the circle at S.


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