In the adjoining figure- sin-7585- Then BC-

The correct option is D 75 mWe have, sinθ=7585 In ABC, sinθ=BCAC Therefore, BC85=7585 So, BC=75 m Hence, this is the answer. ...

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Standard X

Mathematics

Complementary Trigonometric Ratios

In the adjoin...

Question

In the adjoining figure, $sin θ = \frac{75}{85}$ . Then $B C =$

85

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65

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95

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75

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Solution

The correct option is D $75$ m
We have,
$sin θ = \frac{75}{85}$

In $△ A B C,$
$sin θ = \frac{B C}{A C}$

Therefore,
$\frac{B C}{85} = \frac{75}{85}$

So,
$B C = 75 m$

Hence, this is the answer.

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Compute the mode from the following data:
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In the adjoining figure, sinθ=7585. Then BC=

The correct option is D 75mWe have,sinθ=7585In △ ABC,sinθ=BCACTherefore,BC85=7585So,BC=75 mHence, this is the answer.

In the adjoining figure, $sin θ = \frac{75}{85}$ . Then $B C =$

The correct option is D $75$ m
We have,
$sin θ = \frac{75}{85}$

In $△ A B C,$
$sin θ = \frac{B C}{A C}$

Therefore,
$\frac{B C}{85} = \frac{75}{85}$

So,
$B C = 75 m$

Hence, this is the answer.