Question

In the adjoining figure, the area of parallelogram AFEB is 140 $c{m}^2$. Find the area of the triangle ADC.

• A.
• B.
• C.
• D. Data insufficient

Answer 1

The correct option is C

Since the parallelogram AFEB and ABCD are on the same base AB and between the same parallels FC // AB, so they are equal in area.

So, the area of parallelogram = 140 $c{m}^2$

$\Delta$ ADC and parallelogram ABCD are on the same base DC and between the same parallels DC // AB, so the area of the triangle ADC is half the area of parallelogram ABCD.

Area of triangle ADC = $\frac{1}{2}\times 140c{m}^2$

= 70 $c{m}^2$