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Question

In the adjoining figure, the coefficient of friction between wedge (of mass M) and block (of mass m) is μ.

Find the minimum horizontal force F required to keep the block stationary with respect to wedge.


A
Fmin=2μsmg(2m+Mm+M)
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B
Fmin=μsmg(m+M2m+M)
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C
Fmin=g(m+Mμ)
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D
Fmin=μsmg(2m+Mm+M)
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Solution

The correct option is C Fmin=g(m+Mμ)

FBD of m with respect to wedge (real + one pseudo force)with respect to wedge block is stationary.Fx=0=Fymg=μN and N=maa=gμand F=(M+m)a=(M+m)gμ


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