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Question

In the adjoining figure, the position time graph of a particle of mass 0.1 kg is shown. The impulse at t=2s is :
617717_92bd5a9ca2464a83ad693afdf03f0739.png

A
0.02kgm/s
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B
0.1kgm/s
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C
0.2kgm/s
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D
0.4kgm/s
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Solution

The correct option is C 0.2kgm/s
From the graph we can say, upto t = 2.0 s, the body moves with a constant velocity

Slope of position-time graph velocity(V)=42=2m/s

After t=2.0s, position-time graph is parallel to time axis i.e., body comes to rest.

Change in velocity(dv)=2m/s

Impulse = Change in momentum =mdv=0.1×2=0.2kgm/s

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