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Perpendicular Bisector

In the adjoin...

Question

In the adjoining figure, the sides BA and CA have been produced such that BA = AD and CA = AE. Prove that DE || BC. [Hint:- use the concept of alternate angles.]

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Solution

Since BD is the transversal for lines ED and BC and alternate angles () are equal, ED || BC.

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Similar questions

In the figure, the sides BA and CA have been produced such that BA = AD and CA = AE, Prove that segment DE || BC.

B A

C A

B A = A D

C A = A E

D E ∥ B C

B A

C A

Δ A B C

Q

P

A P = A Q

P B = Q C

B A

△ A B C

D

C D = C A

C B

E

∠ B A C = 106^{0}

∠ A B E = 128^{0}

∠ B C D

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