Question

In the adjoining figure, the value of $\angle A+\angle B+\angle C+\angle D+\angle E+\angle F$ in degrees is

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Answer 1

From $△$ ABC;

$\angle A+\angle B+\angle C={180}^{\circ }$

From $△$ DEF;

$\angle D+\angle E+\angle F={180}^{\circ }$

So, adding these

$\angle A+\angle B+\angle C+\angle D+\angle E+\angle F=1{80}^{\circ }+{180}^{\circ }={360}^{\circ }$