Question

In the adjoining figure two blocks of masses $8kg,6kg$ are placed on a horizontal smooth surface. Find the acceleration of each block and contact force between the blocks. Also find the force exerted by the horizontal surface on each block.

Answer 1

The acceleration of each block is same.

$a=\frac{70N}{\left(8+6\right)kg}=5m/s^2$

Contact force is equal to

$F=ma$

$F=\left(6\times 5\right)N=30N$

Force exerted by the horizontal surface is equal to sum of weight and the vertical force on the body.

Force on first body

$N_1=\left(8\times 10+30\right)N=110N$

$N_2=\left(6\times 10+20\right)N=80N$