In the adjoining ray-diagram are given the positions of an object O, image I and two lenses L1 and L2. The focal length of L1 is also given. Find the focal length of the lens L2.
A
30cm
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B
−30cm
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C
−15cm
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D
−60cm
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Solution
The correct option is D−60cm 1v−1u=1f,f=+15cm,u=−40cm 1v−1−40=115,v=+24cm This image acts as object for lens L2 So, u=+(24−4)=+20cm v=30cm f=? 1f=1v−1u⇒1f=1+30−1+20 f=−60cm