Question

In the analysis of an organic compound, it was found that it contains 7 carbon atoms, there are two C = C bonds and one $C\equiv C$ bond. This compound is a hydrocarbon. Hydrocarbons have only carbon and hydrogen elements. On structural analysis, it was found that it is covalent in nature and expected structure is given above.

Calculate the total number of $\pi$ bonds in $s{p}^2-s{p}^2$ carbons present in the given structure?

• A. 3
• B. 4
• C. 1
• D. 2

Answer 1

Answer: (D)

2

In the given compound, there are 2 (1 $\pi$ + 1 $\sigma$ ) double bonds and 1 (2 $\pi$ + 1 $\sigma$ ) triple bond.

Hybridisation of C with double bond is $s{p}^2$.

Hybridisation of C with triple bond is $sp$.

There are 2 $s{p}^2-s{p}^2$ carbons present in the structure.

Hence, 1 $s{p}^2-s{p}^2$ has 1 $\pi$ bond.

Therefore, No of $\pi$ bonds $=2$

Hence, option D is correct.