In the Argand plane, the vector z=4−3i is turned in the clockwise sense through 180o and stretched three times. The complex number represented by the new vector is
A
12 + 9i
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B
12 - 9i
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C
-12 - 9i
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D
-12 + 9i
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Solution
The correct option is D -12 + 9i |z|=√42+(−3)2=5 Let z1 be the new vector obtained by rotating z in the clockwise sense through 180o, therefore z1=e−iπz=(cosπ−isinπ). i.e. z=−4+3i The unit vector in the direction of z−1 is −45+35i Therefore required vector =3|z|(−45+35i)=15(−45+35i)=−12+9i