Question

In the aromatic substitution reaction of $C_6{H}_{5}Y,$ the major product (> 60%) is m-isomer, so the group Y is

• A. $-COOH$
• B. $-Cl$
• C. $-OH$
• D. $-N{H}_2$

Answer 1

The correct option is A $-COOH$

$-COOH$ group is a meta directing (electron-withdrawing) group as it tries to pull the electrons out of the ring. But $-OH,-N{H}_2$ are ortho-para directing groups. $-Cl$ has one exception, it is an electron withdrawing group, but it is ortho-para directing group. Thus major product is m-isomer in case of $-COOH$ group only as all the other three groups are ortho-para directing.