In the arrangement, $11$ wires each of resistance $5 Ω$ are used as sides of cube. A potential difference of $70 V$ is maintained between corners $A$ and $B$ of cube. Current flowing in wire $E F$ is :

4 A

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2 A

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5 A

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10 A

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Solution

The correct option is C $10 A$
The equivalent circuit diagram is as shown in the given figure.
$R_{A B} = \frac{7 r}{5}$

$I = \frac{5 V}{7 r} = \frac{5 \times 70}{7 \times 5} = 10 A$

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