Question

In the arrangement shown below, the acceleration of the 3 kg block is
[Given: $g=10m/s^2$ and inclined plane is smooth]

• A. $2m/s^2$
• B. $1m/s^2$
• C. $0.5m/s^2$
• D. $1.25m/s^2$

Answer 1

The correct option is B $1m/s^2$



Let a be the acceleration of the blocks.
$m_1=2kg$
$m_2=3kg$
$\theta ={30}^0$
For the block of mass $m_2$:
$T–m_{2}gsin{30}^0=m_{2}a$
For the block of mass $m_1$:
$m_{1}g–T=m_{1}a$
$\Rightarrow 20–T=2a$ …..(ii)
Adding (i) and (ii):
$5=5a$
$\Rightarrow a=1m{s}^{–2}$
Thus, the acceleration of the block of mass 3 kg is $1m{s}^{–2}$.
Hence, the correct answer is option (2).