Question

In the arrangement shown, by what acceleration (in ${ms}^{-2}$) the boy must go up so that $100kg$ block remains stationary on the wedge. The wedge is fixed and friction is absent evervwhere. (Take $g=10m/s^2)$

• A. 6.0
• B. 6
• C. 6.00

Answer 1

Answer: (A), (B), (C)

For block to be stationary $T=800N$
If man moves up by acceleration 'a'

$T-mg=ma\Rightarrow 800-500=50a\Rightarrow a=6m/s^2$