wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In the arrangement shown in Fig. 1.16 the bodies have masses m0,m1,m2, the friction is absent, the masses of the pulleys and the threads are negligible. Find the acceleration of the body m1. Look into possible cases.
1092410_0f4ee74da38243fba695fd73210ed0aa.png

Open in App
Solution

Let us write Newton's second law for masses m1 and m2 and moving pully in vertical direction along positive x axis (Fig.):
m1gT=m1w1x
m2gT=m2w2x
T12T=0 (as m=0)
or T1=2T
Again using Newton's second law in projection from for mass m0 along positive x1 direction (Fig.), we get
T1=m0w0
The kinematical relationship between the accelerations of masses give in term of projection on the x axis
w1x+w2x=2w0
Simultaneous solution of the obtained give equations yields:
w1=4m1m2+m0(m1m2)]g4m1m2+m0(m1+m2)
In vector form
w1=[4m1m2+m0(m1m2)]g4m1m2+m0(m1+m2)

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Second Law of Motion
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon