In the arrangement shown in figure above the bodies have masses m0, m1 and m2, the friction is absent, the masses of the pulleys and the threads are negligible. Find the acceleration of the body m1. Look into possible cases.
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Solution
Let us write Newton's second law for masses m1 and m2 and moving pulley in vertical direction along positive x-axis (figure shown below): m1g−T=m1w1x (1) m2g−T=m2w2x (2) T1−2T=0(asm=0) or T1=2T (3) Again using Newton's second law in projection form for mass m0 along positive x1 direction (figure shown below), we get T1=m0w0 (4) The kinematical relationship between the accelerations of masses gives in terms of projection on the x-axis w_{1x}+w_{2x}=2w_0 (5) Simultaneous solution of the obtained five equations yield: w1=[4m1m2+m0(m1−m2)]g4m1m2+m0(m1+m2) In vector form →w1=[4m1m2+m0(m1−m2)]→g4m1m2+m0(m1+m2)