In the arrangement shown in figure, coefficient of friction between the two blocks is μ=12. The force of friction acting between the two blocks is
A
8N
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B
10N
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C
6N
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D
4N
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Solution
The correct option is A8N Assuming both the blocks move together
Acceleration of system =20−24+2=3ms−2
For upper block w.r.t. lower block
f=F1+ma=2+2(3)=8N
For upper block limiting friction is fL=μmg=10N
As f<fL, upper block will not slip over second block ie both the blocks will move together.