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Byju's Answer

Standard XII

Physics

Parallel and Series Combination of Capacitors

In the arrang...

Question

In the arrangement shown in figure, dielectric constant $k_{1} = 2$ and $K_{2} = 3$ . If the capacitance across P and Q are $C_{1}$ and $C_{2}$ respectively, then $\frac{C_{1}}{C_{2}}$ will be (the gaps shown are negligible)

1:1

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2:3

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9:5

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25:24

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Solution

The correct option is D 25:24
$\frac{C_{1}}{C_{2}} = \frac{(\frac{K_{1} + K_{2}}{2})}{(\frac{2 K_{1} K_{2}}{K_{1} + K_{2}})}$
$= \frac{5 \times 5}{2.2 \times 6} = \frac{25}{24}$

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In the arrangement shown in figure, dielectric constant k1=2 and K2=3. If the capacitance across P and Q are C1 and C2 respectively, thenC1C2will be (the gaps shown are negligible)

The correct option is D 25:24C1C2=(K1+K22)(2K1K2K1+K2)=5×52.2×6=2524

In the arrangement shown in figure, dielectric constant $k_{1} = 2$ and $K_{2} = 3$ . If the capacitance across P and Q are $C_{1}$ and $C_{2}$ respectively, then $\frac{C_{1}}{C_{2}}$ will be (the gaps shown are negligible)

The correct option is D 25:24
$\frac{C_{1}}{C_{2}} = \frac{(\frac{K_{1} + K_{2}}{2})}{(\frac{2 K_{1} K_{2}}{K_{1} + K_{2}})}$
$= \frac{5 \times 5}{2.2 \times 6} = \frac{25}{24}$