In the arrangement shown in ﬁgure mA=mB=2 kg. String is massless and pulley is frictionless. Block B is resting on a smooth horizontal surface, while friction coefﬁcient between blocks A and B is μ=0.5. What maximum horizontal force F can be applied so that block A does not slip over the block B? (g=10 m/s2)
Net horizontal force on block B is zero.
Hence, the given figure (a) can be replaced by figure (b).
Block B moves due to friction.
Therefore, maximum common acceleration of the two blocks can be