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Question

In the arrangement shown in figure, the ends P and Q of an inextensible string move downwards with uniform speed u. Pulleys A and B are fixed. The mass M moves upwards with a speed

1814_31ee5b07f28048e08591451ef948a35a.png

A
2ucosθ
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B
u/cosθ
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C
2u/cosθ
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D
ucosθ
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Solution

The correct option is B u/cosθ
The correct option is B.

Given,

P and θ are exentissible string Speed=u,mass=m

So, The point on the thread just connected to mass m will also have the same velocity,

The component of the velocity along the thread is vcosθ. It means any point on the thread must be having with speed vcosθ

vcosθ=uv=ucosθ

987998_1814_ans_ad224dc4df84494ea3d2935a5b2cd778.png

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