Question

In the arrangement shown in figure, when switch $S$ is closed, find the final charge on the $6\mu F$ capacitor :

• A. $12\mu C$
• B. $24\mu C$
• C. $32\mu C$
• D. $48\mu C$

Answer 1

The correct option is C $32\mu C$

In the close loop, $\Delta q$ charge is flowing in the circuit
$\frac{q_0-\Delta q}{C_1}-\frac{\Delta q}{C_2}-\frac{\Delta q}{C_2}=0$
$\frac{q_0}{C_1}=\Delta q[\frac{1}{C_1}+\frac{1}{C_2}+\frac{1}{C_3}]$
$\Delta q=\frac{q_0}{C_1[\frac{1}{C_1}+\frac{1}{C_2}+\frac{1}{C_3}]}=\frac{192}{[1+3+2]}=32\mu C$