In the arrangement shown in given figure current from A to B is increasing in magnitude. Induced current in the loop will
have clockwise direction
We have ∈ind=–ddtϕ. The flux lines are coming out of the plane of the loop (using right hand rule) and hence ϕ is + ve as the current is increasing ddt is also + ve. Thus
∈ind = – (+) (+) = –
Since ∈ind is – ve the induced current is clockwise.