Question

In the arrangement shown in the figure, all surfaces are frictionless, pulleys and string are light. The masses of the blocks are $m_1$=20m1=20 will be if F = 180 N is applied according to figure.

• A. $a_{m_1}=9m/s^2,a_{m_1}=0$
• B. $a_{m_1}=9m/s^2,a_{m_2}=9m/s^2$
• C. $a_{m_1}=0,a_{m_2}=9m/s^2$
• D. None of these

Answer 1

The correct option is A $a_{m_1}=9m/s^2,a_{m_1}=0$

we see that block $M_2$ will remain stationary as there will not be any direct forces were acting hence it's acceleration will be 0
now draw F.B.D of smaller block we find
T=$M_1$a
where T=F=180NEWTON
hence $a_{m_1}$=$\frac{180}{20}$=9m/${sec}^2$
$a_{m_2}$=0