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Pulley

In the arrang...

Question

In the arrangement shown in the Figure all surfaces are frictionless, the masses of the block are $m_{1} = 20 k g$ and $m_{2} = 30 k g$ . The accelerations of masses $m_{1}$ and $m_{2}$ will be if $F = 180 N$ .

a_{m_{1}} = 9 m / s^{2}, a_{m_{2}} = 0

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a_{m_{1}} = 9 m / s^{2}, a_{m_{2}} = 9 m / s^{2}

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a_{m_{1}} = 0, a_{m_{2}} = 9 m / s^{2}

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None of these

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Solution

The correct option is A $a_{m_{1}} = 9 m / s^{2}, a_{m_{2}} = 0$
For mass $m_{1}$
$F = m a$
$a_{m_{1}} = \frac{F}{m} = \frac{180}{20} = 9 m / s^{2}$
$a_{m_{1}} = 9 m / s^{2}$
For mass $m_{2}$
There would be no force on $m_{2}$ , there is only tension on $m_{1}$ that is $F$ because the pulley is ideal mass less and frictionless if there is friction between $m_{1}$ and $m_{2}$ then $m_{2}$ would have acceleration but there is no friction so, acceleration of $m_{2}$ will be zero.
$a_{m_{2}} = 0$

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