In the arrangement shown in the figure, coefficient of friction between the two blocks is, μ=0.5. The force of friction acting between the two blocks is
A
8N
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B
10N
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C
6N
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D
4N
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Solution
The correct option is A8N Free body diagram of the two bodies are as follows
Let us assume that the two blocks move together with common acceleration towards left is ac. Then, ac=f−22=20−f4 or, 2f−4=20−f or, f=8N Maximum friction between the two blocks can be fmax=μmAg=(0.5)(2)(10)=10N Since, f<fmax, it means our assumtion is right Therefore, friction force between the two blocks is f=8N