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Question

In the arrangement shown in the figure, coefficient of friction between the two blocks is, μ=0.5. The force of friction acting between the two blocks is


A
8 N
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B
10 N
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C
6 N
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D
4 N
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Solution

The correct option is A 8 N
Free body diagram of the two bodies are as follows


Let us assume that the two blocks move together with common acceleration towards left is ac.
Then, ac=f22=20f4
or, 2f4=20f
or, f=8 N
Maximum friction between the two blocks can be
fmax=μmAg=(0.5)(2)(10)=10 N
Since, f<fmax, it means our assumtion is right
Therefore, friction force between the two blocks is f=8 N

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