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Question

In the arrangement shown in the figure, find the tensions in the rope and accelerations of the masses m1 and m2 and pulleys P1 and P2 when the system is set free to move. Assume the pulleys to be massless and strings are light and inextensible.
770190_e79f1d92d4ca4caeb1e18336b6a4b1f3.png

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Solution

Given,
In an arrangement shown in the fig.
Finding the tension in the rope and acceleration of the masses m1 and m2 and pulley.
m1<m2
Now,
m2 will be go down word with an acceleration a. Tension on both sides of the pulley will be same.
Let, it be T let us consider forces towards mass m1
Here downward force is
=mgT
It is also equal to m1a
Therefore,
m1gT=m1a(1)
On the other side m is moving upwards so upwards forces
=Tm2g it is also equal tom2a so
Tm2g=m2a(2)
From equation (1)and(2)
m1gm2g=m1a+m2aa=(m1m2)gm1+m2
Also from equation (1) and (2)
T=2m1m2gm1+m2

1219417_770190_ans_0f5c42b0724244a6a49d6f7e02c9e306.png

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