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Question

In the arrangement shown in the figure mass of the block A and body B are 2m, 8m respectively. The surface between body B and floor is smooth. The body B is connected to block C by means of pulley. If the whole system is released then the minimum value of mass of the block C so that the block A remains stationary with respect to B is (Coefficients of friction between A and B is μ)




A
mμ
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B
2mμ+1
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C
10mμ
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D
10mμ1
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Solution

The correct option is D 10mμ1
a=mg2m+8m+m=gμ
m=10mμ1

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