In the arrangement shown in the figure mass of the block A and body B are 2m, 8m respectively .The surface between B and floor is smooth. The body B is connected to block C by means of pulley. If the whole system is released then the minimum value of mass of the block C so that the block A remains stationary with respect to B is (Coefficients of friction between A and B is $μ$ )

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D

For body to be relatively at rest $a_{m} i n$ = $\frac{g}{μ}$ And from 2 nd law $a_{m} i n$ = $\frac{(M) g}{M + 10 m}$
Solving the above equations M = $\frac{10 m}{μ - 1}$

Suggest Corrections

Similar questions

Q. In the arrangement shown in the figure mass of the block

B

and

A

are

2 m, 8 m

respectively. Surface between

B

and floor is smooth. The block

B

is connected to block

C

by means of a pulley. If the whole system is released then the minimum value of mass of the block

C

so that the block

A

remains stationary with respect to

B

is (Co-efficient of friction between

A

and

B

μ

)

In the arrangement shown in the figure mass of the block A and body B are 2m, 8m respectively. The surface between body B and floor is smooth. The body B is connected to block C by means of pulley. If the whole system is released then the minimum value of mass of the block C so that the block A remains stationary with respect to B is (Coefficients of friction between A and B is $μ$ )