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Byju's Answer

Standard XII

Physics

Law of Conservation of Mechanical Energy

In the arrang...

Question

In the arrangement shown in the figure mass of the block B and A are 2 m, 8 m respectively. Surface between B and floor is smooth. The block B is connected to block C by means of a pulley. If the whole system is released then the minimum value of mass of the block C so that the block A remains stationary with respect to B is: (Co-efficient of friction between A and B is $μ$ and pulley is ideal)

\frac{m}{μ}

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\frac{2 m}{μ - 1}

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\frac{10 m}{1 - μ}

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\frac{10 m}{μ - 1}

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Solution

The correct option is D $\frac{10 m}{μ - 1}$

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In the arrangement shown in the figure mass of the block A and body B are 2m, 8m respectively. The surface between body B and floor is smooth. The body B is connected to block C by means of pulley. If the whole system is released then the minimum value of mass of the block C so that the block A remains stationary with respect to B is (Coefficients of friction between A and B is $μ$ )

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The correct option is D 10mμ−1

The correct option is D $\frac{10 m}{μ - 1}$