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Question

In the arrangement shown in the figure weight A possesses mass m, a pulley B possesses mass M. Also known are the moment of inertia I of the pulley to its axis and the radii of the pulley are R and 2R respectively. Consider the mass of the threads is negligible. Find the acceleration of weight A after the system is set free. (Assume no slipping takes place anywhere and axis of cylinder remains horizontal).
864530_f2c7714ed91c4ebd9082ffaf25c7cb23.png

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Solution

Let us depict the forces acting on the pulley and weight A< and indicate positive direction for x and φ as shown in the figure. For the cylinder from the equation Fx=mw and Nex=Icβz we get
Mg+TA2T=Mwc
and 2TR+TA(2 R)=Iβ=IwcR
For the weight A from the equation
Fx=mwx
mgTA=mwA
As there is no slipping of the threads on the pulleys.
wA+wc+2βR=wc+2wc=3wc
Simultaneous solutions of above equations gives:
wA=3(M+3m)g(M+9m+IR2)

1790800_864530_ans_cdfcedc000f644038dccf1923e975b06.png

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