Question

In the arrangements coefficient of friction between the two blocks is $\mu =\frac{1}{2}.$The force of friction acting between the two blocks is :-

• A. 8 N
• B. 6 N
• C. 10 N
• D. 12 N

Answer 1

The correct option is A 8 N

R.E.F image

Solution FBD will be as

So, $f=\left(2\right)a$

$F-f=4\left(a\right)$

$\Rightarrow F-f=2\left(2a\right)\Rightarrow F-f=2f$

$\Rightarrow F=3f\Rightarrow f=\frac{2y}{3}=8N$

As $f=8N<\pi \left(20\right)$ i.e $10N^3$, the

friction is static and the acceleration of

both the block is same

option - A is correct.