In the atom of an element X, 6 electrons are present in the outermost shell. If it acquires a noble gas configuration by accepting requisite number of electrons, then what would be the charge on the ion so formed?

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Solution

Element X has 6 electrons present in the outermost shell of its atom.
In order to complete its octet, the element X acquires 2 electrons, it will form a negatively charged ion i.e., anion ( $X^{2 -}$ ) where the charge on the anion is -2.

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In the atom of an element X, 6 electrons are present in the outermost shell. If it acquires a noble gas configuration by accepting requisite number of electrons, then what would be the charge on the ion so formed?

Element X has 6 electrons present in the outermost shell of its atom. In order to complete its octet, the element X acquires 2 electrons, it will form a negatively charged ion i.e., anion (X2-) where the charge on the anion is -2.

Element X has 6 electrons present in the outermost shell of its atom.
In order to complete its octet, the element X acquires 2 electrons, it will form a negatively charged ion i.e., anion ( $X^{2 -}$ ) where the charge on the anion is -2.