In the Baeyers process:

A l_{2} O_{3}

goes into solution as soluble

A l (O H)_{4}^{-}

while other basic oxides as

T i O_{2}

and

F e_{2} O_{3}

remain insoluble.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

A l_{2} O_{3}

changes to AIN which in turn decomposed by

H_{2} O

No worries! We‘ve got your back. Try BYJU‘S free classes today!

A l_{2} O_{3}

changes to

A l_{2} (C O_{3})_{3}

which changes to

A l C l_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of the above is correct

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is C None of the above is correct
In the bayer's process, the ore containing ferric oxide as the main impurity is digested at about 423K in presence of concentrated NaOH solution in an autoclave. Alumina is converted to soluble sodium meta aluminate $4 N a A l O_{2}$ .The insoluble impurities such as of ferric oxide are removed by filtration. The solution containing sodium meta aluminate is mixed with freshly prepared aluminium hydroxide to precipitate sodium meta aluminate in the form of aluminium hydroxide.

Suggest Corrections

Similar questions

n- Octane in the presence of Cr₂O₃/Al₂O₃ at 873K changes to

A l_{2} O_{3}

A l C l_{3}

C a O

M g O

C O_{2}

S O_{3}

N a_{2} O

Z n O

A l_{2} O_{3}

F e_{2} O_{3}

A l_{2} O_{3}

F e_{2} O_{3}

F e_{2} O_{3 (s)} + 2 A l_{(s)} \to 2 F e_{(l)} + A l_{2} O_{3 (s)}

Join BYJU'S Learning Program