In the balanced chemical reaction,
$I O_{3}^{-} + a I^{-} + b H^{+} ⟶ c H_{2} O + d I_{2}$
a, b, c and d respectively correspond to

5, 6, 3, 3

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

5, 3, 6, 3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3, 5, 3, 6

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5, 6, 5, 5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
5, 6, 3, 3

$I O_{3}^{-} + a l^{-} + b H^{+} ⟶ C H_{2} O + d l_{2}$
Step 1: $I^{- 1} ⟶ I_{2} (o x i d a t i o n)$
$I O_{3}^{-} ⟶ I_{3} (r e d u c t i o n)$
Step 2: $2 I O_{3}^{-} + 12 H^{+} ⟶ I_{2} + 6 H_{2} O$
Step 3: $2 I O_{3}^{-} + 12 H^{+} + 10 e ⟶ I_{2} + 6 H_{2} O$
$[2 I^{-} ⟶ I_{2} + 2 e] \times 5$
Step 5: $I O_{3}^{-} + 5 I^{-} + 6 H^{+} ⟶ 3 I_{2} + 3 H_{2} O$
On comparing, a=5, b=6, c=3, d=3

Suggest Corrections

Similar questions

In the balanced chemical reaction,
$I O_{3}^{-} + a I^{-} + b H^{+} ⟶ c H_{2} O + d I_{2}$
a, b, c and d respectively correspond to

I O_{3}^{-} + a I^{-} + b H^{+} \to c H_{2} O + d I_{2}

I^{-}

{I O_{3}}^{-}

H^{+}

I^{-} + {I O_{3}}^{-} + H^{+} \to I_{2} + H_{2} O

H_{2} S + {F e}^{3 +} ⟶ {F e}^{2 +} + S ↓ + H^{\oplus}

I^{⊖} + I O_{3}^{⊖} + H^{\oplus} ⟶ I_{2} + H_{2} O

B i (s) + N O_{3}^{⊖} + H^{\oplus} ⟶ N O_{2} + {B i}^{3 +} + H_{2} O

I^{⊖} + O_{2} (g) + H_{2} O ⟶ I_{2} + ⊖ O H

C u (s) + {A u}^{\oplus} ⟶ A u (s) + {C u}^{2 +}

I O_{3}^{-} + a I^{-} + b H^{+} \to c H_{2} O + d I_{2} a, b, c, d repectively correspond to :

Join BYJU'S Learning Program