Question

In the basic CsCl (Cesium
chloride) crystal, Cs+ ions form the corners of a cube and a Cl- ion is
at the centre of cube. Edge length is 0.40 nm.
a) What is the magnitude of the net electrostatic force exerted on
Cl- ion by the eight Cs+ ions.?
(b) If one of the Cs+ ion is missing the crystal is said to have defect.
How much will be the force on chlorine ion in that case?
answer fast

Answer 1

$$\begin{gathered} Thedis\tan cebetweenclandCsatomis\frac{\sqrt{3}}{2}adis\tan cewhereaistheside. \\ nowmagnitudeoftehforcewillbe8times\frac{e^2}{4\pi {\epsilon }_0(\frac{\sqrt{3}}{2}a{)}^2} \\ =\frac{8(1.6\times {10}^{-19})(9\times {10}^9{)}^2}{{\displaystyle \frac{\sqrt{3}}{2}}\times 0.4}=\frac{103.68}{.3464}=299.30N \\ \left(b\right)isonesightismis\sin gthenthemagnitudeoftehforcewillbe \\ =\frac{7(1.6\times {10}^{-19})(9\times {10}^9{)}^2}{{\displaystyle \frac{\sqrt{3}}{2}\times 0.4}}=261.88N \end{gathered}$$