In the below figure, BC= ___.

4 cm

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3 cm

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6 cm

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8 cm

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Solution

The correct option is D 8 cm
Given that $O A ⊥ B C .$
Using Pythagoras' theorem in $△ O A B,$ we have
$O B^{2} = O A^{2} + A B^{2} .$
$⟹ 5^{2} = 3^{2} + A B^{2}$
$⟹ A B = 4 c m$
We know that the perpendicular drawn from the centre of a circle to the chord bisects the chord.
$⟹ A B = A C$
$⟹ B C = 2 \times A B = 2 \times 4 = 8 c m$

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Similar questions

In the above figure, AB = 7 cm & BC = 9 cm. Find the length of CD.

In the figure given below AB = 3 cm, AC = 5 cm and AD = 4 cm and D is the midpoint of BC. Then the length of BD is :

D E ∥ B C

D E = 4 c m

B C = 8 c m

A (△ A D E) = 25 {c m}^{2}

A (△ A B C)

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