In the below figure, ΔAEC and ΔDBF are equilateral. Prove that all other triangles are equilateral. (Given that bases of the triangles are parallel).
[4 MARKS]
Steps : 2 Marks
Application of theorem: 1 Mark
Proof : 1 Mark
As given in question ΔAEC and ΔDBF are equilateral so angle made at vertexes =60∘
∠AEC=∠AMB=60∘ (Corresponding Angles) because FB∥EC.
Similarly ∠ACE=∠ANM=60∘ (Corresponding Angles).
For ΔAMN, from above two conditions, we find out the remaining two angles ∠AMB and ∠ANM=60∘
Hence all angles of ΔAMN are equal to 60∘.
Now consider ΔBNO, ∠FBD=60∘ (it is the vertex of equilateral triangle) and ∠BNO=60∘ (vertically
Opposite Angles)
∠BON=60∘ (Angle sum property of triangle). Hence ΔBNO is also equilateral.
Similarly we can prove it for remaining triangle.