In the below figure if AP=BP, AQ=BQ, then AM=BM?

True

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False

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Data insufficient

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Cannot be determined

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Solution

In the given figure,
AP = BP (Given)
AQ = BQ (Given)
PQ is common.
So, $Δ$ PAQ $≅$ $Δ$ PBQ (SSS rule).
$\Rightarrow ∠$ APQ= $∠$ BPQ (CPCT).
Also, AP = BP (Given) and PM is common
Hence, $△$ PMA $≅$ $△$ PMB (SAS Rule)

So, AM = BM

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Similar questions

In the below-shown figure if AP=BP, AQ=BQ, then can we say that AM=BM?

In the given figure if AP=BP, AQ=BQ, then can we say that AM=BM?

In the below-shown figure if AP=BP, AQ=BQ, then can we say that APBQ forms a kite. State true/False.

A P = A Q

B P = B Q .

A B

∠ P A Q

∠ P B Q .

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